find the su m of (-42)+(12)+(-50)+(-17)
Answers
Answer:
Answer:
(i) x + 3 = 0
LHS = x + 3
Put x = 3, we get
LHS = 3 + 3 = 6 ≠ RHS
So, the equation is not satisfied.
(ii) x + 3 = 0
LHS = x + 3
Put x = 0, we get
LHS = 0 + 3 = 3 ≠ RHS
So, the equation is not satisfied.
(iii) x + 3 = 0
LHS = x + 3
Put x = -3, we get
LHS = -3 + 3 = 0 = RHS
So, the equation is satisfied.
(iv) x - 7 = 1
LHS = x - 7
Put x = 7, we get
LHS = 7 - 7 = 0 ≠ RHS
So, the equation is not satisfied.
(v) x - 7 = 1
LHS = x - 7
Put x = 8, we get
LHS = 8 - 7 = 1 = RHS
So, the equation is satisfied.
(vi) 5x = 25
LHS = 5x
Put x = 0, we get
LHS = 5 * 0 = 0 ≠ RHS
So, the equation is not satisfied.
(vii) 5x = 25
LHS = 5x
Put x = 5, we get
LHS = 5 * 5 = 25 = RHS
So, the equation is satisfied.
(viii) 5x = 25
LHS = 5x
Put x = -5, we get
LHS = 5 * (-5) = -25 ≠ RHS
So, the equation is not satisfied.
(ix) m/3 = 2
LHS = m/3
Put m = -6, we get
LHS = -6/3 = -2 ≠ RHS
So, the equation is not satisfied.
(x) m/3 = 2
LHS = m/3
Put m = 0, we get
LHS = 0/3 = 0 ≠ RHS
So, the equation is not satisfied.
(xi) m/3 = 2
LHS = m/3
Put m = 6, we get
LHS = 6/3 = 2 = RHS
So, the equation is satisfied
Step-by-step explanation:
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