Find the subof the bases of a trapezium whose altitude is 0.11m and whose area is o. 55m square
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area of trapezium = 1/2 * height ( sum of bases )
0.55 = 1/2 * 0.11 ( sum of bases )
( sum of bases ) = 0.55 / ( 1/2* 0.11 )
= 55/100 / 1/2*11/100
= 55/100 * 200/11 = 10m
Hence the sum of bases of the trapezium is 10 m
0.55 = 1/2 * 0.11 ( sum of bases )
( sum of bases ) = 0.55 / ( 1/2* 0.11 )
= 55/100 / 1/2*11/100
= 55/100 * 200/11 = 10m
Hence the sum of bases of the trapezium is 10 m
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