Chemistry, asked by anu1234568, 2 months ago

find the substance oxidized and reduced from the following chemical reaction mno2 + 4 HCL gives mncl2 + H2O + cl2​

Answers

Answered by Anonymous
0

At a basic level:

✨The substance oxidized is HCl.

✨The substance reduced is MnO2.

✨Thus, the reducing agent is HCl and the oxidizing agent is MnO2.

Higher Understanding:

=> In MnO2, the oxidation state of Manganese in +4. (Mn+4)

=> In MnCl2, the oxidation state of Manganese is +2. (Mn+2)

So, decrease in positive oxidation state indicates gain of electrons or reduction in MnO2, thus MnO2 is reduced.

=> In HCl, the oxidation state of Chlorine is -1 (Cl-1)

=> In Cl2 (Chlorine gas) the oxidation state of Chlorine is 0.

So, increase in oxidation state indicates loss of electrons or oxidation in HCl, thus HCl is oxidized.

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