find the suitable identity of 95 into note 105
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Here , we have 95 × 105 !!
95 = 100 - 5
105 = 100 + 5
Hence , 95 x 105 = (100 - 5 )(100+5)
It is in the form of (a+b)(a-b) = a²- b²
Thereby , we have solved using appropriate identity !
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Identities :
Identity I: (a + b)²= a² + 2ab + b²
Identity II: (a – b)²= a²– 2ab + b²
Identity III: a² – b²= (a + b)(a – b)
Identity IV: (x + a)(x + b) = x² + (a + b) x + ab
Identity V: (a + b + c)²= a² + b² + c² + 2ab + 2bc + 2ca
Identity VI: (a + b)³ = a³+ b³ + 3ab (a + b)
Identity VII: (a – b)³ = a³– b³ – 3ab (a – b)
Identity VIII: a³+ b³ + c³– 3abc = (a + b + c)(a² + b² + c²– ab – bc – ca)
The above might help you while solving problems !!
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