Find the sum 1 /(1 + 2 )+ 1 /(1 + 2 + 3 )+ · · · + 1/( 1 + 2 + · · · + 51)
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Answer:
11+11+2+…+11+2+…+n
We know that1+2+…+n=n(n+1)2
Therefore, thenthterm is
Tn=1n(n+1)2=2n(n+1)=2(n+1−n)n(n+1)=2[1n−1n+1]
Step-by-step explanation:
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