Find the sum 1+(1+2)+(1+2+3)+......to n terms of the series
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hii
here is ur solution
given that,
1 + 3 + 6 + ............... nth
a = 1
d = a2 - a1
d = 3 - 1 = 2
and a3 - a2
d 6 - 3 = 3
In the given question the common difference are not equal, hence it is not an AP so we can not find the sum of nth term.
hope it helps you
here is ur solution
given that,
1 + 3 + 6 + ............... nth
a = 1
d = a2 - a1
d = 3 - 1 = 2
and a3 - a2
d 6 - 3 = 3
In the given question the common difference are not equal, hence it is not an AP so we can not find the sum of nth term.
hope it helps you
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