Question

Find the sum: 1) 2 + 4 + 6 + ...+ 200 2) 3 + 11 + 19 + ... + 803 3) (-5) + (-8) + (-11)+...+(-230) 4) 34 + 32 + 30 +...+ 10 5) 18 + 15x1/2+ 13 + ...+ (-49x1/2) {this is a question from arithmetic progression }

Answer 1

Step-by-step explanation:

GIVEN:  a=2

              d=4-2

                =2

an=a+(n-1)d

200=2+(n-1)2

200-2=2n-2

198+2=2n

THEREFORE, n=100

sn=$\frac{n}{2}$(a+l)

   =$\frac{100}{2}$(2+200)

  =50*202

  =10100

THEREFORE,THE SUM OF THE FIRST PROGRESSION IS 10100

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