Question

find the sum 1 square + 2 square + 3 square +.......+23 square​

Answer 1

Answer:

5244

Step-by-step explanation:

Hello!!

Here is your answer

Sum of squares of n natural numbers is

$\frac{n(n + 1)(2n + 1)}{6}$

applying this

n = 23

$\frac{23(23 + 1)(56 + 1)}{6} = 4 \times 23 \times 57$

= 92*57

= 644+4600 = 5244

Answer 2

Answer:

The sum of 1 Square + 2 Square + 3 Square , etc, 23 Square is 4324

Step-by-step explanation:

Sum of squares of n natural numbers is

$Sn=\frac{n(n+1)(2n+1)}{6}$

Here, n= 23

So,

$S 23 = \frac{23*(23+1)([2*23]+1)}{6}$

$=\frac{23*24*(46+1)}{6}$

$=\frac{23*24*(46+1)}{6}$

$=\frac{552*47}{6}$

$=\frac{25944}{6}$

$=4324$

So, the sum of first 23 natural numbers is 4324