Question

Find the sum. 11 + 20 + 29 + ... + 4052=11+20+29+...+4052

Answer 1

frst find the value of n by using:a1=a+(n-1)d
then n is 450.so we have 450 terms.

so the sum is:n/2(2a+(n-1)d)
225(22+(224×9))

6966

Answer 2

Answer:

914175

Step-by-step explanation:

El primer término, a1 S 450

​

S 450= 2

(a 1 +a n ) ⋅n= 2

(11+4052)⋅450= 2

4063 ⋅450

=2031,5(450)

=914,175