Find the sum 3+6+9+.....+48
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Answer:
Sum of given series is 408.
Step-by-step explanation:
Series: 3 + 6 + 9 + ...... + 48
Common difference (d) = 6 - 3 = 3
First Term (a) = 3
Last term (b) = 48
No. of terms (n) = 16
Thus,
Sum = n/2 × (a +b)
= 16/2 × (3 + 48)
= 8(51)
= 408.
Answered by
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The answer is 48
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