Math, asked by aiyyappan2006, 7 months ago

Find the sum 3+6+9+.....+48

Answers

Answered by Anonymous
0

Answer:

Sum of given series is 408.

Step-by-step explanation:

Series: 3 + 6 + 9 + ...... + 48

Common difference (d) = 6 - 3 = 3

First Term (a) = 3

Last term (b) = 48

No. of terms (n) = 16

Thus,

Sum = n/2 × (a +b)

= 16/2 × (3 + 48)

= 8(51)

= 408.

Answered by mahabaig3
0
The answer is 48


Plz mark me as brainliest
Similar questions