Find the Sum:34+32+30+....+10
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Answered by
1
Answer:
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Step-by-step explanation:
a=34,
d=32−34=−2
an=10
or, a+(n−1)d=10
or, 34+(n−1)(−2)=10
or, −2(n−1)=−24
or, n−1=12
⇒n=13
∴S13=213[2(34)+12(−2)]
=213×2[34−12]
=13×22=286.
Answered by
1
Answer:
I hope you get your answer
thnx for asking
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