find the sum
34+32+30........................ +10
girishnaik315pedmq6:
using ap method
Answers
Answered by
6
a = 34
cd = -2
10 = 34 + ( n - 1 ) * -2
- 24 / -2 = ( n - 1 )
13 = n
Sn = 13 / 2 * 44 = 13 * 22 = 286 Ans.
cd = -2
10 = 34 + ( n - 1 ) * -2
- 24 / -2 = ( n - 1 )
13 = n
Sn = 13 / 2 * 44 = 13 * 22 = 286 Ans.
Answered by
13
Answer:
286
Step-by-step explanation:
Given, Series is 34 + 32 + 30 + ... + 10.
Clearly this series is in A.P.
First term = 34.
Common difference = -2
Last term = 10.
Let n be the number of terms.
an = 10
⇒ a + (n - 1) * d = 10
⇒ 34 + (n - 1) * (-2) = 10
⇒ 34 - 2n + 2 = 10
⇒ n = 13
∴ Sum = (n/2)[a + l]
= (13/2)[34 + 10]
= 13[22]
= 286.
Therefore, Sum is 286.
Hope it helps!
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