Find the sum [4-1/n] + [4-2/n] + [4-3/n]...Upto n terms
Answers
Answered by
1
Answer: (7-n)/n OR (7/n-1)
Step-by-step explanation:
We have ,
d=[4-2/n]-[4-1/n]
=2/n-3/n
=-1/n
a=[4-1/n]
=3/n
Sn=2a+[n-1]d
=2.3/n+[n-1](-1/n)
=6/n+[(1-n)/n]
=(6+1-n)/n
=(7-n)/n OR (7/n-1)
Similar questions