Question

find the sum 5 4/9 and 3 1/6​

Answer 1

The sum of $5\dfrac{4}{9}$ and $3\dfrac{1}{6}$ = $8\dfrac{11}{18}$ or, $\dfrac{155}{18}$

Step-by-step explanation:

We have,

$5\dfrac{4}{9}$ and $3\dfrac{1}{6}$

To find, the sum of $5\dfrac{4}{9}$ and $3\dfrac{1}{6}$ = ?

∴ $5\dfrac{4}{9}$ and $3\dfrac{1}{6}$

= 5 + $\dfrac{4}{9}$ + 3 + $\dfrac{1}{6}$

= (5 + 3) + ($\dfrac{4}{9}$ + $\dfrac{1}{6}$)

The LCM of 9 and 6 = 18

= 8 + $\dfrac{2\times 4+3\times 1}{18}$

= 8 + $\dfrac{8+3}{18}$

= 8 + $\dfrac{11}{18}$

= $\dfrac{18\times 8+11}{18}$

= $\dfrac{144+11}{18}$

= $\dfrac{155}{18}$

=  $8\dfrac{11}{18}$

∴ The sum of $5\dfrac{4}{9}$ and $3\dfrac{1}{6}$ = $8\dfrac{11}{18}$ or, $\dfrac{155}{18}$

Answer 2

The sum 5 4/9 and 3 1/6​ is 8 11/18

The given fractions are 5 4/9 and 3 1/6. These fractions are improper.

So, first we have to convert the improper fractions into proper fractions.

5 4/9 = [(9*5)+4]/9 = 49/9

3 1/6 = [(3*6)+1]/6 = 19/6

Converting the denominators into a common one [ie LCM of 6,9 = 18]

So, 49/9 = 98/18 and,

19/6 = 57/18

So, 98/18 + 57/18 = (98+57)/18

= 155/18

= 8 11/18