Question

find the sum 6-8√5 and 4+2√5​

Answer 1

Answer❣

Question :

An object travels 20m in 4s and then other 20m in 10s . What is the average speed of the object ?

Solution :

As per the question we have two cases so let's assume each as Case 1 and Case 2 respectively !

Case 1 :

Distance Covered : 20m

Time taken : 4 sec

Speed : Distance / time

: 20 / 4

: 5 m / sec

Case 2 :

Distance Covered : 20 m

Time taken : 10 sec

Speed : Distance / time

: 20 / 10

: 2 m / sec

huge average speed = total distance total time

averagespeed=totaltimetotaldistance

= \5 + 2 4 + 10=4+105+2

= 7 40 = 0.175=407=0.175

Hence , the average speed of the object is 0.175 m / sec !!

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Answer 2

Answer:

Question 7

Q7) Without adding, find the sum.

(i) 1 + 3 + 5 + 7 + 9

(ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19

(iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

Solution:

(i) Here, there are five odd numbers. Therefore square of 5 is 25. 1 + 3 + 5 + 7 + 9 = 5^25

2

= 25

(ii) Here, there are ten odd numbers. Therefore square of 10 is 100. 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 10^210

2

= 100

(iii) Here, there are twelve odd numbers. Therefore square of 12 is 144.

1 + 3 +5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23 = 12^212

2

= 144

Step-by-step explanation:

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