Question

Find the sum : -7/5 + 2/3​

Answer 1

GIVEN :-

-7/5 + 2/3

To FIND :-

Sum of given value : -7/5 + 2/3

SOLUTION :-

Lcm of 5 and 3 = (5 x 3) = 15.

$\therefore\sf{ \frac{ - 7}{5} + \frac{2}{3} } \: = \frac{3 \times ( - 7) + 5 \times 2}{15} = \frac{ - 21 + 10}{15} = \frac{ - 11}{5}$

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$\sf</strong><strong>\</strong><strong>p</strong><strong>i</strong><strong>n</strong><strong>k</strong><strong>{</strong><strong> </strong><strong>(</strong><strong>i</strong><strong>)</strong><strong> </strong><strong>E</strong><strong>x</strong><strong>i</strong><strong>s</strong><strong>t</strong><strong>e</strong><strong>n</strong><strong>c</strong><strong>e</strong><strong> </strong><strong> \:</strong><strong>o</strong><strong>f</strong><strong> </strong><strong> \:</strong><strong>A</strong><strong>d</strong><strong>d</strong><strong>i</strong><strong>t</strong><strong>i</strong><strong>v</strong><strong>e</strong><strong> </strong><strong> \:</strong><strong>I</strong><strong>n</strong><strong>v</strong><strong>e</strong><strong>r</strong><strong>s</strong><strong>e</strong><strong>}</strong><strong> </strong><strong>$

For every rotational number a/b , there exists number -a/b

$\sf Such \: that, (\frac{ \alpha }{b} + \frac{- \alpha }{b} ) = \frac{ \alpha + ( - \alpha ) }{b} = \frac{0}{b} = 0 \\ \sf \:And \: similarily, \: ( \frac{ - \alpha }{b} + \frac{ \alpha }{b} ) = 0 \\ \sf Thus,( \frac{ \alpha }{b} + \frac{ - \alpha }{b} ) = ( \frac{ - \alpha }{b} + \frac{ \alpha }{b} )</strong><strong>\\</strong></p><p><strong>\pink \star \sf \frac{ - \alpha }{b} \: is \: called \: the \: additive \: inversw \: of \: \frac{ \alpha }{b} .$