Question

find the sum all natural numbers between 200and 300 exactly divisible by 6

Answer 1

hey brother !!!!!!!

here is ur answer....................

first no. will be = a = 204
d = 6
last term be = p = 300
now,
the total no. of such terms = n = ( 300 - 204 ) / 6
this implies
n = 96 / 6
n = 16
sum of all of the terms between 204 and 300 which are divisible by 6 will be......
= 16 / 2 x ( a + p )
= 8 x ( 204 +300 )
= 8 x 504
= 4032

hope it would be helpful to you
if so,
pls mark it as brainliest

Answer 2

Step-by-step explanation:

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