Find the sum and product of its zeroes is root 2 ,-1/3
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Hey buddy here is ur answer .....
ZEROES :
alpha = 2 ,
beta = -1/3
Now ;
→ x^2 + (sum of zero) x + (product of zero)
→ x^2 + (alpha)x + (beta)
→ x^2 + (2)x + (-1/3)
→ x^2 + 2x + (-1/3)
→ x^2 + 2x -1/3
BE BRAINLY !!
HoPe U LiKe AnSwEr
^_^
ZEROES :
alpha = 2 ,
beta = -1/3
Now ;
→ x^2 + (sum of zero) x + (product of zero)
→ x^2 + (alpha)x + (beta)
→ x^2 + (2)x + (-1/3)
→ x^2 + 2x + (-1/3)
→ x^2 + 2x -1/3
BE BRAINLY !!
HoPe U LiKe AnSwEr
^_^
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