find the sum and product of roots (x+a) (x-b)=0
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(x + a)(x - b) = x(x - b) + a(x - b)
= x² - bx + ax - ab
= x² -(b-a)x +(-ab)
we know, any quadratic equation is in the form of
= x² -(sum of roots)x + product of roots
compare both equation, we get
sum of roots = (b - a)
product of roots = -ab
= x² - bx + ax - ab
= x² -(b-a)x +(-ab)
we know, any quadratic equation is in the form of
= x² -(sum of roots)x + product of roots
compare both equation, we get
sum of roots = (b - a)
product of roots = -ab
justice2:
sum of roots will be b- a ok
yep, now see i correct it
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