Question

Find the sum and product of t^2-4t-5=0.Plz give the correct answer only it's very urgent plz help.​

Answer 1

Answer:

4, -5

Step-by-step explanation:

$in \: a {x}^{2} + bx + c = 0 \\ \\ if \: \: \alpha \: and \: \beta \: are \: roots \: then \\ \\ \alpha + \beta = - \frac{b}{a} \\ \\ \alpha \beta = \frac{c}{a} \\ \\ here \: given \: {t}^{2} - 4t - 5 = 0 \\ \\ = > sum = - \frac{( - 4)}{(1)} = 4 \\ \\ = > prod = \frac{( - 5)}{(1)} = - 5$

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