Question

find the sum and product of the roots of equation 16x^2-24x+1=0​

Answer 1

Answer:

1.5, 1/16

Step-by-step explanation:

16x²-24x+1=0

compare it with the general equation of quadratic..

16x²-24x+1=0

ax²+bx+c=0

a=16 b=-24 c=1

a+b=-b/a =24/16 =3/2 =1.5

ab=c/a =1/16

Answer 2

Answer:

=> The sum is $\frac{3}{2}$ and the product is $\frac{1}{16}.$

Step-by-step explanation:

Given that,

$16x^2-24x+1=0$

To find:- The sum and the product of the roots of the equation,

The standard equation is:

$ax^2+bx+c=0$

Therefore,

$a=16, b = -24, c =1$

As we know that,

For calculating the sum, we have

$\alpha+\beta=-\frac{b}{a}$

Substitute the values, we get

=> $\alpha+\beta=\frac{-(-24)}{16}$

=> $\alpha+\beta=\frac{3}{2}$

For calculating the product, we have

$\alpha \cdot \beta=\frac{c}{a}$

Substitute the values, we get

$=> \alpha \cdot \beta=\frac{1}{16}$