Question

Find the sum and product of the roots of the quadratic equations 3+1÷a=10÷a^2​

Answer 1

Answer:

sum of root

$= > - b \a$

$3 + 1 \div a = 10 \div a { }^{2} \\ = > \frac{3 + 1}{a} = \frac{10}{a {}^{2} } \\ = > 3a {}^{2} + a {}^{2} = 10a \\ = > 4a {}^{2} - 10a = 0$

apply formula