Math, asked by rahul200544, 8 months ago

Find the sum and product of the zeroes of polynomials
(i) x2 - 16​

Answers

Answered by DrNykterstein
2

p(x) = x² + 0x - 16

Here,

a = 1 , b = 0, c = -16

Sum of Zeroes = - b/a

==> sum of zeroes = 0

Product of Zeroes = c / a

==> product of zeroes = - 16

Answered by lepakshikalyan2006
1

Answer:

sum=0,product=-16

Step-by-step explanation:

sum of zeroes= -b/a= 0/1=0

product of zeroes =c/a= -16/1= -16

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