Question

find the sum and product of the zeros of the following quadratic equation. X^2 - 8​

Answer 1

Answer:-

sum of the zeros = 0

Explanation:-

Given:-

Quadraric equation,

x²-8 = 0

To Find:-

Sum of the zeros

Solution:-

$\boxed{\bold{Sum \: of \: zeros = \dfrac{- Co-efficient \: of \: {x}^{2}}{Co-efficient \: of \: x}}}$

${\rightarrow} \: \dfrac{-(0)}{1}$

${\rightarrow} \: 0$

Answer 2

GIVEN:-

Quadratic equation is x²-8

TO FIND:-

Sum and product of the roots

EXPLANATION:-

let α and β be the roots of the given quadratic equation

we need to find sum and product of roots

we know that

Sum of roots.

$\boxed{ \sf \: \alpha + \beta = \dfrac{ - coefficient \: of \: x}{coefficient \: of \: {x}^{2} } }$

Here in the equation,

x²-8=0

>a=1

>b=0

>c=-8

substituting the values

$\alpha + \beta = \dfrac{0}{1} = 0$

Product of roots

$\boxed{ \sf \alpha \beta = \dfrac{constant \: term}{coefficent \: of \: {x}^{2} } }$

substituting

$\alpha \beta = \dfrac{ - 8}{1} = - 8$