Question

find the sum and product of zeroes of p(x)=2(x^2-1)+3x-9

Answer 1

Hey

Here is your answer,

2(x^2-1)+3x-9=0
2x^2 -2 +3x -9=0
2x^2 +3x -11=0

Sum of zeroes= -b/a
Alpha + beta = -3/2

Product of zeroes = c/a
Alpha x beta = -11/2

Hope it helps you!