.Find the sum and product of zeroes of p(x)=√2x^2-3x-2√2.
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Hey
Here is your answer,
√2x^2-3x-2√2=0
Sum of zeroes = -b/a
=-(-3)/√2
=3/√2
Product of zeroes =c/a
=-2√2/√2
=2
Hope it helps you!
Here is your answer,
√2x^2-3x-2√2=0
Sum of zeroes = -b/a
=-(-3)/√2
=3/√2
Product of zeroes =c/a
=-2√2/√2
=2
Hope it helps you!
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