Math, asked by Anonymous, 1 year ago

.Find the sum and product of zeroes of p(x)=√2x^2-3x-2√2.

Answers

Answered by sijasubbiah
0
Hey

Here is your answer,

√2x^2-3x-2√2=0

Sum of zeroes = -b/a

=-(-3)/√2
=3/√2

Product of zeroes =c/a

=-2√2/√2
=2

Hope it helps you!
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