Find the sum and product of zeroes of the polynomial 100x²-81.
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100x2-81
100x2=81
x2=81/100
x=9/10
100x2=81
x2=81/100
x=9/10
Answered by
1
100x square - 81. ans. Here we must use the equation a square - bsquare = (a+b)(a-b). So, (10x) square - (9)square. This can be expressed as. (10x+9)(10x ....= 9/10 x
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