Find the sum and product of zeroes
of the polynomial x²-8-2x.
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Step-by-step explanation:
x² - 2x - 8 = 0
x² - 4x + 2x - 8 = 0
x( x - 4) + 2( x - 4) = 0
(x -4) ( x + 2) = 0
Either,
x - 4 = 0
: x = 4
or,
x + 2 = 0
: x = - 2answer
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