Find the sum and product of zeroes of the quadratic polynomial 3x²-x-4
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Answer:
By splitting the middle term,
3x²-x-4
= 3x²+3x-4x-4
= 3x(x+1)-4(x+1)
= (3x-4)(x+1)
So, the zeroes of the polynomial are x = 4/3 and x = -1.
Sum = 4/3 + (-1) = 4/3 - 1 = 1/3
Product = 4/3 × (-1) = -4/3
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