Question

find the sum and product of zeroes
$x \: ^{2} - 4 \sqrt{3x + 9}$
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Answer 1

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Answer 2

x^2 - 3 root3 x - root3 x + 9
x( x- 3 root3) - root3 ( x - 3 root3)
( x - 3 root3 ) . ( x - root 3 )

Therefore
zeroes are (i) 3 root3 (ii) root3

Sum of zeroes =
3 root3 + root3 = 4 root3

Product of zeroes =
3 root3 x root3 = 9