Question

find the sum and product of zeros of polynomial 2x^3-4x^2+3x-8

Answer 1

Hey!!!!

=> 2x³ - 4x² + 3x - 8

So

$= > \alpha + \beta + \gamma = \frac{ - b}{a}$

$= > \alpha + \alpha + \gamma = \frac{4}{2}$

$= > \alpha + \beta + \gamma = 2$

So,

$= > \alpha \beta \gamma = \frac{ - d}{a}$

$= > \alpha \beta \gamma = \frac{8}{2}$

$= > \alpha \beta \gamma = 4$


Hope this helps ✌️

Answer 2

Here is the solution.
If you still have any doubts .....comment it.