find the sum and product of zeros of quadratic polynomials P(x)=6x²-3-7x
Answers
Answered by
9
Answer:
7/6
-1/2
Step-by-step explanation:
6x^2-7x-3
=6x^2-9x+2x-3
= 3x(2x-3)+1(2x-3)
=(3x+1)(2x-3)
x =-1/3. , 3/2
sum = 3/2- 1/3 = 7/6
product = -1/2
Answered by
1
Answer:
6x^2-3-7x also can be written as 6x-7x-3
6x^2-9x+2x-3
=3x(2x-3)+1(2x-3)
=(3x+1)(2x-3)
now the zeroes are -1/3;3/2
sum of the zeroes =3/2-1/3=7/6
product of the zeroes = 3/2×-1/3=-3/6=-1/2
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