find the sum and products of zeroes of a polynomial x^+5x-8
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Answered by
0
Answer:
sum is - 5 and product is -8
Answered by
0
Answer:
x^2+5x-8
sum of zeroes=-b/a
sum of zeroes=-(5)/1
sum of zeroes=-5
Now,
Product of zeroes=c/a
Product of zeroes=(-8)/1
Product of zeroes= -8
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