Question

find the sum frist 22terms of the AP:8,3,-2​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge{\bold{\underline{Solution:-}}}$

Given:-

AP: 8 , 3 , -2......

To Find:-

Sum of the first 22terms = ?

Solve:-

We know that fomula:

$sum \: = \frac{n}{2} [2a \: + ( n - 1 )d \: ]$

Here,

n = 22

first term, a = 8

common difference , d = -5

Putting the values in formula we get;

$= \frac{22}{2} [2 \times 8 + (22 - 1) - 5]$

$= 11 [ (16 + (21)( - 5) ]$

$= 11[16 - 105]$

$= 11 \times ( - 89)$

$= - 979$

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