Math, asked by keerthikak843, 1 month ago

Find the sum invested to earn Rs 10800 per annum, if the rate of interest is 9% per year.​

Answers

Answered by InsaanGamer
0

Answer:

Here, Principal (P) = Rs. 10800, Time (n) = 3 years Rate of interest (R) = 12\ \frac{1}{2}\%=\frac{25}{2\%}Amount(A) = P\left(1+\frac{R}{100}\right)^n= 10800\left(1+\frac{1}{8}\right)^3=10800\left(\frac{9}{8}\right)^3= 10800\times\frac{9}{8}\times\frac{9}{8}\times\frac{9}{8}= Rs. 15,377.34Compound Interest (C.I.) = A – P= Rs. 10800 – Rs. 15377.34 = Rs. 4,577.34(b) Here, Principal (P) = Rs. 18,000, Time (n) = 2\ \frac{1}{2} years, Rate of interest (R) = 10% p.a.Amount(A) = P\left(1+\frac{R}

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