Math, asked by Sssbadsha6813, 10 months ago

Find the sum of 0.40 + 0.43 + 0.46 + ... + 1

Answers

Answered by MaheswariS
5

\textbf{Given:}

0.40+0.43+0.46+..............+1

\textbf{To find:}

\text{Sum of the given A.P series}

\textbf{Solution:}

\text{Consider}

0.40+0.43+0.46+..............+1

\text{This is a finite A.P series with $a=0.40$ and $d=0.03$}

\textbf{Number of terms in the A.P series}

\boxed{\bf\,n=\frac{l-a}{d}+1}

n=\dfrac{1-0.40}{0.03}+1

n=\dfrac{0.60}{0.03}+1

n=\dfrac{60}{3}+1

n=20+1

\implies\bf\,n=21

\textbf{Sum of the n terms of the A.P series}

\boxed{\bf\,S_n=\dfrac{n}{2}[a+l]}

S_{21}=\dfrac{21}{2}[0.40+1]

S_{21}=\dfrac{21}{2}[1.40]

S_{21}=21[0.70]

\bf\,S_{21}=14.7

\therefore\textbf{The sum of $0.40+0.43+0.46+..............+1$ is 14.7}

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