. Find the sum of 1 +2 +3 +…80
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EXPLANATION.
Sum = 1 + 2 + 3 + . . . . . + 80.
As we know that,
Formula of :
Sum of first n natural number = ∑n = [n(n + 1)]/2.
Using this formula in the equation, we get.
⇒ (80)(81)/2 = 40 x 81 = 3240.
MORE INFORMATION.
Some important results.
(1) = Sum of first n natural numbers = ∑n = [n(n + 1)]/2.
(2) = Sum of first n odd natural number = ∑(2n - 1) = n².
(3) = Sum of first n even natural number = ∑2n = n(n + 1).
(4) = Sum of squares of first n natural number = ∑n² = [n(n + 1)(2n + 1)]/6.
(5) = Sum of cube of first n natural number = ∑(n)³ = [n(n + 1)/2]².
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