Question

Find the sum of 1+3+5+.....+55

Answer 1

Answer:

sum of numbers = 784

Step-by-step explanation:

we have to find sum of numbers . This is an example of arithmetic progression.

In this example

t1 = 1 , t2 = 3 t3 = 5

therefore difference = 2

tn = a+ n-1 × d

55 = 1+(n-1) 2

55 = 1+2n-2

55 =2n-1

55+1=2n

56=2n

56/2= n

28=n

sn = n/2 (t1+tn)

= 28/2 (1+55)

=14×56

= 784

sum of numbers = 784

Answer 2

Step-by-step explanation:

Sum of numbers = 784........