find the sum of 1+3+5+7+9+................+101
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we have to find sigma(2n-1)
sigma(2n -1) =2sigma (n) - sigma(1)
=2×{n(n+1)/2} - n
=n(n+1) - n
=n×n + n - n
=n×n
sigma(2n -1) =2sigma (n) - sigma(1)
=2×{n(n+1)/2} - n
=n(n+1) - n
=n×n + n - n
=n×n
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l think it's helpful to you
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