find the sum of 1, 3, 5, 7, 9, 11 without doing some of it
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HELLO THERE!
Series: 1, 3, 5, 7, 9, 11
Let the first term be a
Let the common difference be d.
Hence, a = 1
d = 3 - 1 = 2
It is clear that the above numbers are in Arithmetic Progression.
Last term l = 11.
Total number of terms (n) = 6
Now, there is a formula of sum of n terms of an AP, which is listed in the attachment.
The sum of the terms by formula is hence 36.
Series: 1, 3, 5, 7, 9, 11
Let the first term be a
Let the common difference be d.
Hence, a = 1
d = 3 - 1 = 2
It is clear that the above numbers are in Arithmetic Progression.
Last term l = 11.
Total number of terms (n) = 6
Now, there is a formula of sum of n terms of an AP, which is listed in the attachment.
The sum of the terms by formula is hence 36.
Attachments:
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