find the sum of 1+3+5+, , , , ,+99
Answers
Answered by
1
Answer:
Step-by-step explanation:
the sum of 1+3+5+.......+99
The first term a = 1
The common difference d = 2
Total number of terms n = 50
apply the input parameter values in the AP formula
Sum = n/2 x (a + Tn)
= 50/2 x (1 + 99)
= (50 x 100)/ 2
= 2500
1 + 3 + 5 + 7 + 9 + . . . . + 99 = 2500
Similar questions