find the sum of 1) 3+6+9+............48 terms 2) 51+52+53+...........+55
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This Math problem can basically can be written as 3 (+1) =4, (+2)= 6, (+3)= 9, (+4)= 13, (+5)= 18, (+6)= 24, (+7)= 31, (+8)= 39, (+9)= 48, (+10)= 58, (+11)= 69, (+12)= 81, (+13)= 94, (+14)= 108, (+15)= 123, (+16)= 139, (+17)= 156, (+18)= 174, (+19)= 193, (+20)= 213...... Adding 4+6+9+13+18+24+31+39+48+58+69+81+94+108+123+139+156+174+193+213= 1600. Which is the Answer.
2......Sum of first N natural numbers ={ N(N+1) }/2.... Sum of first 100 natural numbers = (100×101)/2 = 50×101 = 5050... (i)... Sum of first 50 natural numbers = (50×51)/2 = 25×51 = 1275...
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