find the sum of 1+5+9........325?
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Answered by
4
Step-by-step explanation:
here a = 1, d = 4, an =325
a + (n - 1)d = 325
1 + 4n - 4 = 325
4n = 328
n = 328 / 4 = 82
therefore nth term is 325 and we have to find the sum of the series upto 82nd term.
Sn = (n / 2)( a + an )
= (82 / 2)(1 + 325) = 41 x 326 = 13366
Answered by
0
Step-by-step explanation:
1+5+9+13+17+21+25+29+33+37+41+45+49+53+57+61+65+69+73+77+81+85+89+93+97+101+105+109+113+117+121+125+129+133+137+141 145 149 153 157 161 +165+ 169+173 +177+181+185+189+193+197+201+205+209+213+217+221+225+229+233+237+241+245+249+253+257+261+265+269+273+277+281+285+289+293+297+301+305+309+321+325
I hope it's helpful.
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