Question

find the sum of 1+5+9+........up to 30th terms 10 th std Arithmetic progressions lessons
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Answer 1

Answer:

1170

Step-by-step explanation:

first term (a)= 1

common difference (d)= second term- first term

= 5-1

= 4

Number of terms(n) = 30 (given)

Sum of the terms(S)= n/2 [2a+(n-1)d]

= 30/2 [(2×1)+(30-1)×4]

= 15 [2+(29×4)]

= 15 (2+116)

= 15 × 118

= 1,770.

HOPE YOU HAVE UNDERSTOOD.......

Answer 2

Answer:

first term (a)= 1

common difference (d)= second term- first term

= 5-1

= 4

Number of terms(n) = 30 (given)

Sum of the terms(S)= n/2 [2a+(n-1)d]

= 30/2 [(2×1)+(30-1)×4]

= 15 [2+(29×4)]

= 15 (2+116)

= 15 × 118

= 1,770.

HOPE YOU HAVE UNDERSTOOD.......