find the sum of 10,9⅔,9½...to 11 terms
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a=10 9 2/3 change into improper fraction 29/3 so that 29/3-10 you'll get d = -1/3
Sum of 11 terms
S11=11/2(2a+10d)
S11=11/2(2*10+10*-1/3)
S11= 11/2*(20-1/3)
S11=11/2(59/3)
S11= 649/6
rakshitha34:
thanks
but whether ,it right to keep it in fraction
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