find the sum of 10 terms of an ap -37, -33, -29.....
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since the formula of sum of terms is ..... n/2[2a+ (n-1)d ] ........
so sum of 10 terms of an a.p is .... 10/2 [2×-37 + ( 10 -1 ) 4 ]
S10 = 5 ( -74+36 )
S10 = 5 ( -38 )
S10 = - 190 ......
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