Question

find the sum of 10 terms of an AP. whose pth term is 3p/4+1

Answer 1

Answer:

$s_{10}=33$

Step-by-step explanation:

given,

$p^{th}term \:\:is\frac{3p}{4+1}$

so,

$p_{1}=\frac{3*1}{4+1} =\frac{3}{5}$

similarly

$p_{10} =\frac{3*10}{4+1} =\frac{30}{5} =6\\\\A.P \:is\:\frac{3}{5} ,..,6$

W.K.T(we know that)

$s_{n} =\frac{n}{2} [p_{1}+p_{n}]\\\\s_{10} =\frac{10}{2} [\frac{3}{5} +6]\\\\s_{10} =5 [\frac{33}{5} ]\\\\s_{10} =33$

∴sum of 10 terms of an AP is 33