Question

find the sum of 100 odd numbers starting with 1​

Answer 1

Answer:

10000

Step-by-step explanation:

$S_{n} = \frac{n}{2} [ 2a +(n -1)(d)]\\= S_{100} = \frac{100}{2} [ 2(1) + (100 - 1) (2)\\= S_{100} =  50(2 + (99)(2)\\= S_{100}  = 1000$