find the sum of 100 terms of the AP 0.7,0.71, 0.72
Answers
Answered by
16
the correct ans is 56.5
S = ½(2a + (n-1)d)n
S = ½(2*.7 + (99)*.01)100
S = 50(.14 + (99)*.01)
S = 50(.14 + .99)
S=56.5
S = ½(2a + (n-1)d)n
S = ½(2*.7 + (99)*.01)100
S = 50(.14 + (99)*.01)
S = 50(.14 + .99)
S=56.5
Answered by
25
first term = 0.7
common difference = 0.01
sum of 100 terms =100/2 ( 2×0.7 + 99 × 0.01)
= 50 ( 1.4 + 0.99)
= 50 ( 2.39)
= 119.5
common difference = 0.01
sum of 100 terms =100/2 ( 2×0.7 + 99 × 0.01)
= 50 ( 1.4 + 0.99)
= 50 ( 2.39)
= 119.5
annu347:
this is the right answer. Thanks.....!!
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