Question

Find the sum of 10³+11³+12³+...+20³

Answer 1

Answer:

42075

Step-by-step explanation:

the sum of the cubes for the last number being n is given by

$[n{(n+1)/2}]^2$

so in the first case you have to take n = 20 in this equation and then subtract this answer by the the value of the equation for n=9 for removing the 1^3,2^3......9^3

Answer 2

Answer:

10³+¹¹³+12³+.....2⁰³